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The required equation is given by :
x² - ( Sum of the zeroes) x + ( Product of the Zeros) =0
⟹ x² - ( 5-3 ) x + ( 5 × - 3) = 0
⟹ x² - 2x - 15 = 0
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Answer:
Let the zeroes be alpha and beta
So, alpha = 5 and beta = -3
we know that,
alpha+beta = -b/a
5-3= -b/a
2=-b/a.........(i)
alpha×beta = c/a
5×-3=c/a
-15= c/a..…………(ii)
Comparing (i) and ii
a=1, b=-2 ,c=-15
Therefore, the required polynomial is x²-2x-15.
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