Question

please answer me fast​

Answer 1

Answer:

6

Step-by-step explanation:

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Answer 2

$\sqrt{x + \sqrt{ {x}^{2} - 1 } } = \sqrt{x + \sqrt{8} } \\ squaring \: on \: both \: sides \\ = > x + \sqrt{ {x}^{2} - 1 } = x + \sqrt{8} \\ = > \sqrt{ {x}^{2} - 1 } = \sqrt{8 } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = > {x}^{2} - 1 = 8 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = > x = \sqrt{9} = 3 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

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