Math, asked by Anonymous, 5 months ago

please answer me fast​

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Answered by kumaresh48
1

Answer:

PLEASE MARK AS BRAINLIEST

Step-by-step explanation:

(i) inner curved surface area

According to the question inner diameter is 4 cm,

then,

Inner radius of a cylindrical pipe =r1=2innnerdiameter=(24)cm=2cm

Height (h) of cylindrical pipe=77 cm,

Curved Surface Area of inner surface of pipe  =2πr1h

=(2×722×2×77)cm2

=968cm2

(ii) Outer curved surface area

According to the question outer diameter is 4.4 cm

Outer radius of cylindrical pipe =r2=2outerdiamterer=(24.4)cm=2.2cm

Height of cylinder = h = 77 cm,

Curved area of outer surface of pipe = 2πr2h

=(2×722×2.2×77)cm2

=(2×22×2.2×11)cm2

=1064.8cm2

(iii) Total surface area

Total surface area = curved surface area of inner cylinder + curved surface of outer cylinder + 2 × Area of base

Area of base = area of circle with radius 2.2 cm - Area of circle with radius 2 cm

=πr22−πr12

=7

Answered by tmahak5
3

Step-by-step explanation:

I hope it will be helpful for you

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