Question

please answer me fast

Answer 1

Given Equation is f(x) = 2x^2 + 2ax + 5x + 10.

Given g(x) = (x + a).

By remainder theorem, we get

x + a = 0

x = -a.


Now,

f(-a) = 2(-a)^2 + 2a(-a) + 5(-a) + 10 = 0

       = 2a^2 - 2a^2 - 5a + 10 = 0

       = -5a + 10 = 0

       = -5a = -10

          a = 2.


Hope this helps!

Answer 2

Hi,

Please see the attached file !


Thanks