Math, asked by princejoy007, 1 month ago

please answer me fast ​

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Answered by Anonymous
129

 \hline  \begin{array}{  ||c||} \underline{\underline{\footnotesize \tt{Used  \: law \:  Exponent}}}\\ \footnotesize \tt{{a}^{m} \times  {a}^{n}  =  {a}^{m + n} } \\ \footnotesize \tt{ {a}^{m} \div  {a}^{n}  =  {a}^{m - n} }\\  \underline{\underline{\footnotesize \tt{{a}^{0}  = 1}}}\end{array}

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\dashrightarrow\sf{Solution:-}

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  \dashrightarrow\tt{( \frac{ {x}^{a} }{ {x}^{b} } )^{a + b} \times(  \frac{ {x}^{b} }{{x}^{c} } )^{b + c}  \times(  \frac{ {x}^{c} }{ {x}^{a} })^{c + a}   }

  \dashrightarrow \footnotesize \tt{ ({x}^{a - b}) ^{a + b} \times ({x}^{b - c}) ^{b + c}  \times(  {x}^{c - a} )^{c + a}   }

   \dashrightarrow\footnotesize \tt{{x}^{(a - b)(a + b)} \times{x}^{(b - c)(b + c)} \times  {x}^{(c - a)(c  + a)}    }

  \dashrightarrow \footnotesize \tt{{x}^{a(a + b) - b(a + b)} \times{x}^{b (b + c) - c(b + c)} \times  {x}^{c (c  + a) - a(c + a)}    }

  \dashrightarrow \footnotesize \tt{{x}^{ {a}^{2}   + ab -ab  -  {b}^{2} } \times{x}^{ {b}^{2}  + bc - bc  -   {c}^{2} } \times  {x}^{   { c}^{2} + ac - ac  -  {a}^{2} }    }

   \dashrightarrow\footnotesize \tt{{x}^{ {a}^{2}   +  \cancel{ab}  \cancel{-ab}  -  {b}^{2} } \times{x}^{ {b}^{2}  +  \cancel{bc} \cancel{ - bc } -   {c}^{2} } \times  {x}^{   { c}^{2}  + \cancel {ac } \cancel{- ac } -  {a}^{2} }    }

   \dashrightarrow\footnotesize \tt{{x}^{ {a}^{2}  -  {b}^{2} } \times{x}^{ {b}^{2}  -   {c}^{2} } \times  {x}^{   { c}^{2} -  {a}^{2} }    }

  \dashrightarrow \footnotesize \tt{{x}^{ {a}^{2}  -  {b}^{2}  + {b}^{2}  -   {c}^{2}  +  { c}^{2} -  {a}^{2} }    }

  \dashrightarrow \footnotesize \tt{{x}^{ \cancel {a}^{2}  -   \cancel {b}^{2}  + \cancel {b}^{2}   -    \cancel{c}^{2}  + \cancel  { c}^{2} -  \cancel {a}^{2} }    }

  \dashrightarrow \footnotesize \tt{x}^{ 0  }

\boxed{   \underline{\underline{  \dashrightarrow\footnotesize \tt{1  }}}}

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