please answer me fast.....
Attachments:
Answers
Answered by
1
Given
Mass of ice =200g
T=1min =60sec
Q= mass of ice x latent heat xchange in temperature
Q=200gx336J/g
Q=67200J
Heat transfer rate =Q/t
=67200/60
=1120J/s
As we know latent heat of water =4.2J/g °c
Heat energy gain by water =mass x latent heat of water x change in temperature
=200x4.2x20
=16800J
So time required to raise the temperature upto 20°C
T=Q/R
=16800/1120
=1680/112
=15sec
This is your ans hope it will help you in case of any doubt comment below
Mass of ice =200g
T=1min =60sec
Q= mass of ice x latent heat xchange in temperature
Q=200gx336J/g
Q=67200J
Heat transfer rate =Q/t
=67200/60
=1120J/s
As we know latent heat of water =4.2J/g °c
Heat energy gain by water =mass x latent heat of water x change in temperature
=200x4.2x20
=16800J
So time required to raise the temperature upto 20°C
T=Q/R
=16800/1120
=1680/112
=15sec
This is your ans hope it will help you in case of any doubt comment below
tnwramit1:
tnx for brainliest
Similar questions