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To find QPM:
In ∆QPM,
Q + P + M = 180
=> 50 + P + 90 = 180
(M is 90 because PQ is the diameter)
=> 140 + P = 180
=> P = 180 - 140 = 40
=> QPM = 40°
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To find QPR:
QRPM is a cyclic quadrilateral. So sum of opposite angles is 180
=> MPR + MQR = 180
=> MPR + (65+50) = 180
=> MPR = 180 - 65 - 50
=> MPR = 65
=> QPM+ QPR = 65
=> 40 + QPR = 65
=> QPR = 65 - 40
=> QPR = 25°
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To find PRS:
PQRS is a cyclic quadrilateral. So sum of opposite angles is 180
=> PSR + PQR = 180
=> PSR + 65 = 180
=> PSR = 180-65 = 115°
Now in ∆PRS,
PRS + RSP + SPR = 180
=> PRS + 115 + 40 = 180
=> PRS = 180 - 115 - 40
=> PRS = 25°
In ∆QPM,
Q + P + M = 180
=> 50 + P + 90 = 180
(M is 90 because PQ is the diameter)
=> 140 + P = 180
=> P = 180 - 140 = 40
=> QPM = 40°
__________________________________
To find QPR:
QRPM is a cyclic quadrilateral. So sum of opposite angles is 180
=> MPR + MQR = 180
=> MPR + (65+50) = 180
=> MPR = 180 - 65 - 50
=> MPR = 65
=> QPM+ QPR = 65
=> 40 + QPR = 65
=> QPR = 65 - 40
=> QPR = 25°
__________________________________
To find PRS:
PQRS is a cyclic quadrilateral. So sum of opposite angles is 180
=> PSR + PQR = 180
=> PSR + 65 = 180
=> PSR = 180-65 = 115°
Now in ∆PRS,
PRS + RSP + SPR = 180
=> PRS + 115 + 40 = 180
=> PRS = 180 - 115 - 40
=> PRS = 25°
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