Question

please answer me fast

Answer 1

x = 4/3 y

y = 3/8 y

=> z = 8/3 y


$\text{AB || CD}\\ \\ \text{If You take BC as transversal, }\\ \\ \angle{ABC} +\angle DCB = 180\\ \\ \Rightarrow (x+y) + z = 180 \\ \\ \Rightarrow \frac{4}{3} y + y + \frac{8}{3} y = 180\\ \\ \Rightarrow y \bigg( \frac{4}{3} + 1 + \frac{8}{3} \bigg) = 180 \\ \\ \Rightarrow y \bigg( \frac{4 + 3 + 8}{3} \bigg) = 180 \\ \\ \Rightarrow y \bigg( \frac{15}{3} \bigg) = 180 \\ \\ \Rightarrow 5y = 180 \\ \\ \Rightarrow y = \frac{180}{5} = {36}^{o} \\ \\ x = \frac{4}{3} \: y = \frac{4}{3} \times 36 = {48}^{o} \\ \\ z = \frac{8}{3} \: y = \frac{8}{3} \times 36 = {96}^{o} \\ \\ \boxed{x = {48}^{o}} \: \boxed{y = {36}^{o}} \: \boxed{z = {96}^{o}}$

Answer 2

$\huge\mathcal{\fcolorbox{cyan}{black}{\pink{ĄNsWeR࿐}}}$

x = 4/3 y

y = 3/8 y

=> z = 8/3 y

$\text{AB || CD}\\ \\ \text{If You take BC as transversal, }\\ \\ \angle{ABC} +\angle DCB = 180\\ \\ \Rightarrow (x+y) + z = 180 \\ \\ \Rightarrow \frac{4}{3} y + y + \frac{8}{3} y = 180\\ \\ \Rightarrow y \bigg( \frac{4}{3} + 1 + \frac{8}{3} \bigg) = 180 \\ \\ \Rightarrow y \bigg( \frac{4 + 3 + 8}{3} \bigg) = 180 \\ \\ \Rightarrow y \bigg( \frac{15}{3} \bigg) = 180 \\ \\ \Rightarrow 5y = 180 \\ \\ \Rightarrow y = \frac{180}{5} = {36}^{o} \\ \\ x = \frac{4}{3} \: y = \frac{4}{3} \times 36 = {48}^{o} \\ \\ z = \frac{8}{3} \: y = \frac{8}{3} \times 36 = {96}^{o} \\ \\ \boxed{x = {48}^{o}} \: \boxed{y = {36}^{o}} \: \boxed{z = {96}^{o}}$

HOPE SO IT WILL HELP......