Question

please answer me fast anyone ​

Answer 1

Step-by-step explanation:

given------>

P =1000

r = 8%

$si \: for \: 1st \: year \\ \\ si = \frac{p \times n \times r}{100} \\ \\ si = \frac{1000 \times 8 \times 1}{100} \\ \\ si = 80 \\ \\ \\ for \: 2nd \: year \\ \\ si = \frac{p \times n \times r}{100} \\ \\ si = \frac{1000 \times 8 \times 2}{100} \\ \\ si = 160 \\ \\ for \: 3rd \: year \\ \\ si = \frac{p \times n \times r}{100} \\ \\ si = \frac{1000 \times 8 \times 3}{100} \\ \\ si = 240 \\ \\ \\ now \: for \: c.i \\ \\ \\ for \: 1st \: year \\ \\ a = p \times(1 + { \frac{r}{100} })^{n} \\ \\ a = 1000 \times ({1 + \frac{8}{100} })^{1} \\ \\ a = 1000 \times \frac{108}{100} \\ \\ a = 1080 \\ \\ c.i = a - p \\ \\c. i = 1080 - 1000 \\ \\ 80 \\ \\ \\ for \: 2nd \: year \\ \\ a = p \times(1 + { \frac{r}{100} })^{n} \\ \\ a = 1000 \times (1 + \frac{8}{100} ){}^{2} \\ \\ \\ a = 1000 \times \frac{108}{100} \times \frac{108}{100} \\ \\ \frac{108 \times 108}{10} \\ \\ 1166.4 \\ \\ ci \: = 1166.4 - 1000 \\ \\c i = 166.4 \\ \\ \: fr \: 3rd \: year \\ \\ \\ a = p \times(1 + { \frac{r}{100} })^{n} \\ \\ a \: = 1000 \times (1 + \frac{8}{100} {})^{3} \\ \\ a = 1000 \times \frac{108}{100} \times \frac{108}{100} \times \frac{108}{100} \\ \\ a = \frac{108 \times 108 \times 108}{1000} \\ \\ a = \frac{1259712}{1000} \\ \\ 1259.712 \\ \\ ci = 1259.712 - 1000 \\ \\ ci \: = 259.712$