Question

Please answer me fast I have exam ​

Answer 1

Answer:

which question number

Answer 2

Answer:

Step-by-step explanation:

2. using cos x = sin(90-x)

cos(40+x) = sin (90-40-x) = sin(50-x)

=> 50-x = 30

=> x=50-30=20

3. sin(A+20) = $\sqrt{3}$ /2

=> sn(A+20)= sin60

=>A+20 = 60

=> A= 40

4. Sin A= cos A when A = 45;

5. $sin^{2} 30$+$cos^{2}$ 60 +$tan^{2}$45=

$(1/2)^{2}$ + $(1/2)^{2}$+$1^{2}$

=1/4 +1/4+1=3/2

6. 2$tan^{2}$ 45 + $cos^{2}$30-$sin^{2}$60

=2.$1^{2}$ +$(\sqrt{3}/2 )^{2}$-$(\sqrt{3} /2)^{2}$

=2+3/4-3/4=2