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Answers
Question 1
The area of a parallelogram is 60cm^2 and one of it's altitude is 5cm. The length of the corresponding side is?
Solution :-
Area of parallelogram = l x b
Here,
- l = 5cm
- area = 60cm^2
- b = ?
substituting values in the formula,
area = l x b
60 = 5 x b
60 = 5b
60/5 = b
12 = b
•°• Length of corresponding side is 12cm
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Question 2
If the diagonals of a rhombus gets doubled, then the area of the rhombus becomes ----- it's original area.
Solution :-
Original Area of rhombus = 1/2(d x d')
Here,
- d and d' are the two diagonals.
Now, when we double the diagonals, it becomes
2d and 2d'
and area becomes,
1/2(2d x 2d')
= 1/2(4dd')
= 2dd'
Comparing original area and new area,
•°• The area becomes 4 times the original area.
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Question 3 :-
If the diagonal d of a quadrilateral is doubled and the heights h and h' falling on d are halved, then the area of the quadrilateral is?
Solution :-
Let the quadrilateral be ABCD.
Here,
- AD be height 1 (h)
- BC be height 2 (h')
- AC be the diagonal (d)
Area = 1/2( h + h')d
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Question 4 :-
Area of a traingle is 60cm^2 and altitude is 24cm, then it's corresponding base-?
Solution :-
Area of triangle = 1/2 x b x h
60 = 1/2 x b x 24
60 x 2 = 24b
120 = 24b
b = 120/24
b = 5
•°• length of corresponding base is 5cm
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Question 5 :-
Area of square whose side is 25cm -?
Solution :-
Area of square = s^2
Here,
- s = 25
Area = 25 x 25
•°• Area = 625cm^2
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Question 6 :-
Length of a rectangle whose area is 280cm^2 is 20cm, then breadth is -?
Solution :-
Area of rectangle = 2(l+b)
280 = 2(20 + b)
280 = 40 + 2b
240 = 2b
b = 240/2
b = 120cm
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Question 7 :-
The length of parallel sides of a trapezium are in the ratio 2:3. The distance between parallel sides and its area are 12m and 300m^2 . The lenght of parallel sides are -?
Solution :-
Area of trapezium = 1/2(d1 + d2)h
Here,
- Let the parallel sides be 2x and 3x
- h = 12
300 = 1/2( 2x + 3x ) 12
600 = 5x(12)
600 = 60x
x = 600/60
x = 10
Length of parallel sides,
2x = 2(10) = 20m
3x = 3(10) = 30m
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