Question

please answer me fast please I will mark you as brainliest​

Answer 1

Answer:

Steps of Construction:

(i) Draw a line segment that is sufficiently long using a ruler.

(ii) Locate points Q and R on it such that QR=5 cm

(iii) At Q, construct a line segment QM, sufficiently large, such that ∠MQR at 60°

use protractor to measure 60°

(iv) With Q as centre and radius 4cm, draw the line cutting QM at P, join PR.

Then PQR is the required triangle.

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