Question

please answer me fast
step by step​

Answer 1

Answer:

For first, ( n-3) (2n+1)

n(2n+1)-3(2n+1)

2n^2+n-6n-3

2n^2-5n-3.

For second,

(4n-5) (5n+1)

4n(5n+1) -5(5n+1)

20n^2+4n-25n-5

20^2-21n-5

For third,

(2n+1) (6n-1)

2n(6n-1) 1(6n-1)

12n^2-2n+6n-1

12n^2-4n-1

For Fourth,

(m-3) (3m+5)

m(3m+5) -3(3m+5)

3m^2+5m-9m-15

3m^2-4m-15

For fifth,

(7m+1) (9m-5)

7m(9m-5) 1(9m-5)

63m^2-35m+9m-5

63m^2-26m-5

I hope it helps you.