Question

please answer me find the question no.

Answer 1

(3)

When the temperature is 0 degrees Celsius.

= > F = (C * 9/5) + 32

= > F = (0) + 32

= > F = 32.


Therefore the temperature in Fahrenheit  = 32Degrees.


When the temperature is 0 degrees Fahrenheit

= > C = (F - 32) * 5/9

= > C = (0 - 32) * 5/9

= > C = -32 * 5/9

= > C = -160/9

= > C = -17.777



Therefore the temperature in Celsius = -17.777


(4)

We know that F = (C * 9/5) + 32

= > F = F * 9/5 + 32

= > F - 9/5 F + 32

= > -4F/5 = 32

= > F = (-32 * 5)/4

= > F = -160/4

= > F = -40.



We know that C = (F - 32) * 5/9

= > C = (C - 32) * 5/9

 = > C =  5C - 160/9

= > 9C = 5C - 160

= > 4C = -160

= > C = -40.




Therefore the numerical value of temperature = -40.


Hope this helps!