please answer me for maths
Answers
Step-by-step explanation:
Let the no. of ₹5 coins be x .
Then we have no. of ₹2 coins as 3x .
Let the no. of ₹1 coins be y .
It is given that x + 3x + y = 160
=> 4x + y = 160
=> y = 160 - 4x (i)
Also x ₹5 coins means a value of ₹5x , 3x ₹2 coins means a value of ₹(2 * 3x) = ₹6x , and y ₹1 coins means a value of ₹y .
Hence ₹5x + ₹6x + ₹y = 300 as given
Substituting y from (i) in this equation , we get :-
₹5x + ₹6x + ₹(160 - 4x) = ₹300
=> ₹11x + ₹160 - ₹4x = ₹300
=> ₹7x + ₹160 = ₹300
=> ₹7x = ₹140
=> ₹x = ₹20
Hence ₹y = 160 - 4x = 160 - 80 = ₹80
So no. of ₹2 coins = 3x = 60
No. of ₹1 coins = y = 80
No. of ₹5 coins = x = 20
Answer:
rs 1 = 80 coins
rs 2 = 60 coins
rs 3 = 20 coins
Step-by-step explanation:
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