Question

please answer me for this sum​

Answer 1

Answer:

ye to muje ni aate aapko Kya btau

Answer 2

Given:

cot θ = 1

To find:

(sin ²θ - cos ²θ) / (2 sin ²θ - sin² θ)

Solution:

From given, we have,

cot θ = 1

we use the trigonometric relations, so we have,

cot θ = cos θ/sin θ

therefore, we get,

⇒ cot θ = cos θ/sin θ = 1

⇒ cos θ/sin θ = 1

∴ cos θ = sin θ

⇒cos ²θ = sin ²θ

Now consider,

(sin ²θ - cos ²θ) / (2 sin ²θ - sin² θ)

= (sin ²θ - sin ²θ) / (sin ²θ)

= 0 / (sin ²θ)

= 0

∴ (sin ²θ - cos ²θ) / (2 sin ²θ - sin² θ) = 0