Question

please answer me friends please​

Answer 1

1st answer

$\sf \dashrightarrow \dfrac{x}{3} + 3 = \dfrac{9}{12}$

$\sf \dashrightarrow \dfrac{x + 9}{3} = \dfrac{9}{12}$

$\sf \dashrightarrow 12(x + 9) = 9(3)$

$\sf \dashrightarrow 12x + 108 = 27$

$\sf \dashrightarrow 12x = 27 - 108$

$\sf \dashrightarrow 12x = -81$

$\sf \dashrightarrow x = \dfrac{-81}{12}$

$\sf \dashrightarrow x = \dfrac{-27}{4}$

Hence, the value of x is -27/4.

2nd answer

First, we should find the money left with him after giving to his daughter.

Let the money left after giving to daughter be m.

$\sf \dashrightarrow m - \dfrac{2}{5} \: of \: m = 32000$

$\sf \dashrightarrow m - \dfrac{2}{5} \times m = 32000$

$\sf \dashrightarrow m - \dfrac{2m}{5} = 32000$

$\sf \dashrightarrow \dfrac{5m - 2m}{5} = 32000$

$\sf \dashrightarrow 5m - 2m = 32000 \times 5$

$\sf \dashrightarrow 5m - 2m = 160000$

$\sf \dashrightarrow 3m = 160000$

$\sf \dashrightarrow m = \dfrac{160000}{3}$

$\sf \dashrightarrow m = 53333.33$

Now, we can find that how much money did he have.

Let the money with him at beginning be n.

$\sf \dashrightarrow n - \dfrac{1}{3} \: of \: n = 53333.33$

$\sf \dashrightarrow n - \dfrac{1}{3} \times n = 53333.33$

$\sf \dashrightarrow n - \dfrac{1n}{3} = 53333.33$

$\sf \dashrightarrow \dfrac{3n - 1n}{3} = 53333.33$

$\sf \dashrightarrow 3n - 1n = 53333.33 \times 3$

$\sf \dashrightarrow 3n - 1n = 159999.99$

$\sf \dashrightarrow 2n = 159999.99$

$\sf \dashrightarrow n = \dfrac{159999.99}{2}$

$\sf \dashrightarrow n = 79999.95$

Hence, the the man had ₹79999.95 with him totally.

Answer 2

Answer:

first thanks my answer please