Question

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Speed time graph for the motion of a car is given.


Which part of the graph represents uniform acceleration

(a) OA (b) AB (c) BC (d) AC


Calculate the deceleration of the car as it comes to rest.


In which time interval speed of the train is constant

(a) 0 to 4s (b) 4s to 10s

(c)10s to 16s (d) 0 to 16s


What is the maximum speed gained by the car.

(a) 4m/s (b) 6m/s

(c) 10m/s (d) 16m/s​

Answer 1

Knowledge required:

→ In a velocity time graph, the slope of graph tell us about the acceleration. If the slope is high then the acceleration is positive, if the solve is low then the acceleration is negative and if the slope is parallel to time axis then there is no acceleration taking place!

Solution:

Question: Which part of the graph represents uniform acceleration!?

Answer: Part OA in the graph represents the uniform acceleration of the car.

• AB represents uniform velocity, that is the constant velocity.

• BC represents the uniform retardation of the car.

Question: Calculate the deceleration of the car as it comes to rest.

Answer:

→ Acceleration = Change in the velocity / Time taken

→ a = (v-u)/t

→ a = (0-6)/(16-10)

→ a = -6/6

→ a = -1 mps sq.

→ Retardation = -1 mps sq.

→ Deceleration = -1 mps sq.

Question: In which time interval speed of the car is constant!?

Answer: Between 4 seconds to 10 seconds the speed of the car is constant.

Question: What is the maximum speed gained by the car!?

Answer: Maximum speed gained by the car is 6 metre per second. $\:$