Question

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Answer 1

Answer:

2 and 3

Step-by-step explanation:

♣ Number of digits in 4489 is 4 so, n=4

Since n is even so,

Numbers of digits in square root of 4489 is:

N=n2=42=2

Hence, the total number of digits in the square root of 4489 is 2.

♣ Number of digits in 390625 is 6 so, n=6

Since n is even so,

Number of digits in square root of 390625 is:

N=n2=62=3

Hence, the total number of digits in the square root of 390625 is 3.

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Answer 2

Answer:

Number of digits in square root of 390625 is:

N=n2=62=3

Hence, the total number of digits in the square root of 390625 is 3.

Step-by-step explanation: