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First, isolate sqrt(h^2+r^2) . To do so, divide both sides by pi r .
A/(pir)=(pirsqrt(h^2+r^2))/(pir)
A/(pir)=sqrt(h^2+r^2)
Then, eliminate the radical. So, square both sides of the equation.
(A/(pir))^2=(sqrt(h^2+r^2))^2
(A/(pir))^2=h^2+r^2
To have h^2 only at the right side, subtract both sides by r^2.
(A/(pir))^2-r^2=h^2+r^2-r^2
(A/(pir))^2-r^2=h^2
And, to have h only, take the square root of both sides of equation.
sqrt((A/(pir))^2-r^2)=sqrt(h^2)
sqrt((A/(pir))^2-r^2)=h
Then, simplify left side.
sqrt(A^2/(pi^2r^2)-r^2)=h
sqrt(A^2/(pi^2r^2)-(pi^2r^4)/(pi^2r^2))=h
sqrt((A^2-pi^2r^4)/(pi^2r^2))=h
(sqrt(A^2-pi^2r^4))/(pir)=h
Hence, h=(sqrt(A^2-pi^2r^4))/(pir) .
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A/(pir)=(pirsqrt(h^2+r^2))/(pir)
A/(pir)=sqrt(h^2+r^2)
Then, eliminate the radical. So, square both sides of the equation.
(A/(pir))^2=(sqrt(h^2+r^2))^2
(A/(pir))^2=h^2+r^2
To have h^2 only at the right side, subtract both sides by r^2.
(A/(pir))^2-r^2=h^2+r^2-r^2
(A/(pir))^2-r^2=h^2
And, to have h only, take the square root of both sides of equation.
sqrt((A/(pir))^2-r^2)=sqrt(h^2)
sqrt((A/(pir))^2-r^2)=h
Then, simplify left side.
sqrt(A^2/(pi^2r^2)-r^2)=h
sqrt(A^2/(pi^2r^2)-(pi^2r^4)/(pi^2r^2))=h
sqrt((A^2-pi^2r^4)/(pi^2r^2))=h
(sqrt(A^2-pi^2r^4))/(pir)=h
Hence, h=(sqrt(A^2-pi^2r^4))/(pir) .
Here is the answer mark me a Brainlist
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