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Answered by
2
Answer:
Angle P + Angle Q + Angle R = 180° ⟨Angle Sum Property of ∆⟩
Angle P + 25 ° + 65° = 180°
Angle P = 180° – 90°
Angle P = 90°
So, ∆ PQR is a right angled ∆.
So, According to Pythagoras Theorem,
(perpendicular)²+(base)² = (hypotenuse)²
PQ² + RP² = QR²
So, 2nd option is correct.
Answered by
24
Answer:
BY ANGLE SUM PROPERTY
P = 180- [ 65 + 25 ]
P = 180 -90
P = 90 °
SO , THIS IS A RIGHT ANGLED TRIANGLE
SIDE OPPOSITE TO 90° IS HYPOTENUSE
AND WE T
NOW THAT BY PYTHOGORUS THEORM
SUM OF SQUARES OF ADJACENT SIDES = SQUARE OF HYPOTENUSE
SO WE CAN SAY THAT
PQ² + PR ² = QR ²
Step-by-step explanation:
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