Math, asked by khushboomaharana06, 6 months ago

please answer me!! It's very very urgent​

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Answered by ravi2303kumar
1

Answer:

a=0; b=4/59

Step-by-step explanation:

\frac{8+\sqrt{5} }{8-\sqrt{5}} - \frac{8-\sqrt{5} }{8+\sqrt{5}}

= \frac{(8+\sqrt{5} )^2-(8-\sqrt{5} )^2}{8^2-\sqrt{5}^2 }

= \frac{4(8)(\sqrt{5} )}{64-5}

= \frac{4(8)(\sqrt{5} )}{59}

= 0 + \frac{4}{59}*8\sqrt{5} (which is of the form a+8\sqrt{5} b )

=> a=0; b=4/59

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