Question

please answer me my question correctly please answer hmm​

Answer 1

Sum of interior angles of a pentagon can be given by the formula n-2(180) where n is the no. Of sides, so in the case of a pentagon it is 3(180)
=540 degrees
Since it is a regular pentagon
All the sides and angles are of equal length
So, each angle would be 540/5
=108 degrees
An angular bisector divides the angle into two
So, bisector of D divides angle d into two parts
108/2= 54 degrees
The angular bisector meets at a point p on AB
Since the formed figure of BCDP is a quadrilateral
The sum of all angles will be 360 degrees.
Angle at D=54 degrees
Angle at B=108 degrees because angles in a regular pentagon is 108 degrees
Angle at C is also =108 degrees
Therefore, angle at P = 360-(54+108+108) due to angle sum property
Therefore angle at P =360-270
Angle DPB is equal to 90 degrees
This is your answer and please mark as brainliest answer

Answer 2

Answer:

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