Question

please answer me my question no 29???

Answer 1

Step-by-step explanation:

Given: (sinθ - secθ)² + (cosθ - cosecθ)²

⇒ (sinθ - 1/cosθ)² + (cosθ - 1/sinθ)²

⇒ (sin²θ + 1/cos²θ - 2 sinθ * 1/cosθ) + (cos²θ + 1/sin²θ - 2cosθ*1/sinθ)

⇒ sin²θ + 1/cos²θ - 2sinθ * 1/cosθ + cos²θ + 1/sin²θ - 2 cosθ * 1/sinθ

⇒ (sin²θ + cos²θ) + (1/cos²θ + 1/sin²θ) - 2(sinθ * 1/cosθ + cosθ * 1/sinθ)

⇒ 1 + (sin²θ + cos²θ/cos²θsin²θ) - 2(sin²θ + cos²θ/cosθsinθ)

⇒ 1 + (1/cos²θsin²θ) - 2(1/cosθsinθ)

⇒ 1 + sec²θcosec²θ - 2secθcosecθ

⇒ (1 - secθcosecθ)²

Hope it helps!

Answer 2

Step-by-step explanation:

( sinA - SecA )² + ( cosA - cosecA )²

= ( 1/cosecA - secA )² + ( 1/secA - cosecA )²

= [(1-secAcosecA)/cosecA]²+[(1-secAcosecA)/secA]²

=( 1-secAcosecA)²[1/cosec²A + 1/sec²A ]

= ( 1 - secAcosecA )² [ sin²A + cos²A ]

= ( 1 - secAcosecA )²