please answer me my question
teniteraj bro in maths
Answers
Step-by-step explanation:
Solutions :-
1.
Twice the amount A = 2× x = 2x
10 more than amount B = B+10 = y+10
According to the given problem
Twice the amount of A is Rs. 10 more than the amount B
=> 2x = y+10
=> 2x-y-10 = 0
Required equation is 2x-y-10 = 0
2)
Given equation is 4x+3y = 12
(3,0) is a solution because
LHS =>
=> 4(3)+3(0)
=> 12+0
=> 12
=> RHS
LHS = RHS
3)
3x-7y = 41 passes through the point (2,-5)
Put x = 2 and y = -5 then
LHS = 3(2)-7(-5)
=>6+35
=> 41
=> RHS
=> LHS = RHS
4)
Given equation is (2/3)x -(7/5)y = 2.3
LCM of 3 and 5 = 15
=> (10x-21y)/15 = 2.3
=> 10x-21y =2.3×15
=> 10x-21y = 34.5
=> 10x-21y-34.5 = 0
On comparing with ax+by+c = 0 then
a = 10
b = -21
c = -34.5
5)
Given equation is ax+3y = 1
Point lies on it = (2,-1)
Since it lies on it then it satisfies the given equation
Put x = 2 and y = -1 then
=>a(2)+3(-1) = 1
=> 2a -3 = 1
=> 2a = 1+3
=> 2a = 4
=> a = 4/2
=> a = 2
The value of a = 2
6)
There are infinitely number of many lines passes through the point (2,3)
X+y = 5
2x+3y = 5
3x+4y = 18
and so on
7)
The present age of Ravi = x years
If 10 years added to the age then it will be
(x+10) years
According to the given problem
The age becomes = 25 years
=> x+10 = 25
=> x+10-25 = 0
=> x -15 = 0
The linear equation is x-15 = 0