Question

Please answer me my questions and correct ​

Answer 1

Answer:

answer of 10th question

answer of 11th question

in a regular pentagon all the angles are equal and the sum of angles of a pentagon is 540 degree so

a+b+c+d+e=540

from here

all angles are 108°

now DP is the angle bisector of angle d so angle PDC is is half of 108 degree that is 54° .

now in quadrilateral DCBP,

d+c+b+p=360

so,

p= 90

if help then mark brainliest