Question

please answer me my questions and correct don't fake answer I will report you okay hmmmmm ​

Answer 1

$\huge{\underline{\boxed{ \bf{Question \: 1}}}}$

A wire is in the shape of a rectangle whose dimensions are 46cm × 30cm.

If the same wire is re-bent in the shape of a square Find the side of the square.

$\huge{\underline{\boxed{ \bf{Answer \: 1}}}}$

$\Large\mathfrak{Given} \small{\pink{\begin{cases} \\ \sf\star \red{ Dimension \: of \: Rectangle \: wire = 46cm \times 36cm} \\ \\ \end{cases}}}$

$\Large\mathfrak{Find} \small{\red{\begin{cases} \\ \sf\star \purple{ Side \: of \: Square} \\ \\ \end{cases}}}$

$\Large\mathfrak{Solution}$

We, know that

$\underline{ \boxed{ \sf Perimeter \: of \: Rectangle = 2(l + b)}}$

where,

• Length, l = 46cm
• Breadth, b = 30cm

So,

$\dashrightarrow\sf Perimeter \: of \: Rectangle = 2(l + b)$

$\dashrightarrow\sf Perimeter \: of \: Rectangle = 2(46 + 30)$

$\dashrightarrow\sf Perimeter \: of \: Rectangle = 2(76)$

$\dashrightarrow\sf Perimeter \: of \: Rectangle = 152cm$

$\therefore\sf Perimeter \: of \: Rectangle = 152cm$

Now, It is given that Rectangular wire is re-bent to form a square.

So,

$\large{\underline{\boxed{\sf Perimeter \: of \: Square = Perimeter \: of \: Rectangle}}}$

we, know that

$\underline{ \boxed{ \sf Perimeter \: of \: Square = 4(side)}}$

So,

$:\to\sf Perimeter \: of \: Square = Perimeter \: of \: Rectangle$

$:\to\sf 4(side) =Perimeter \: of \: Rectangle$

where,

• Perimeter of Rectangle = 152cm

So,

$:\to\sf 4(side) =Perimeter \: of \: Rectangle$

$:\to\sf 4(side) =152$

$:\to\sf side= \dfrac{152}{4}$

$:\to\sf side= 38cm$

Hence, Side of Square = 38cm

____________________________

$\huge{\underline{\boxed{ \bf{Question \: 2}}}}$

Find the area of the wall excluding the windows.

$\huge{\underline{\boxed{ \bf{Answer \: 2}}}}$

Given:

• Side of Wall = 8m
• Side of window = 2m

Find:

• Area of wall excluding window

Solution:

We, know that

$\underline{\boxed{\sf Area \: of \: wall = (side) \times (side)}}$

where,

• Side, a = 8m

So,

$\dashrightarrow\sf Area \: of \: wall = (side) \times (side)$

$\dashrightarrow\sf Area \: of \: wall = (8) \times (8)$

$\dashrightarrow\sf Area \: of \: wall =64 {cm}^{2}$

$\therefore\sf Area \: of \: wall =64 {cm}^{2}$

Now,

Again using

$\large{\underline{\boxed{\sf Area \: of \: window = (side) \times (side)}}}$

where,

• Side = 2m

So,

$:\implies\sf Area \: of \: window = (side) \times (side)$

$:\implies\sf Area \: of \: window = (2) \times (2)$

$:\implies\sf Area \: of \: window = 4 {cm}^{2}$

Now, Area of Wall excluding window will be

> Area of wall - 4(Area of Window)

Bcz there are four windows

where,

• Area of wall = 64cm²
• Area of window = 4cm²

So,

> 64 - 4(4)

> 64 - 16 = 48cm²

Hence, area of wall excluding window is 48cm²