Question

please answer me my questions and correct don't fake answer I will report you okay hmmmmm I ​

Answer 1

Given:

• Sugandha Paints the Triangle with red
• She paints the Square with green

Find:

• The area to be painted by the two colors.

Solution:

we, know that

$\large{ \boxed{ \sf Area \: of \: triangle \triangle = \dfrac{1}{2} \times b \times h}}$

where,

• Base = 12m
• Height = 18 - 12 = 6m

So,

$\dashrightarrow\sf Area \: of \: triangle \triangle = \dfrac{1}{2} \times b \times h$

$\dashrightarrow\sf Area \: of \: triangle \triangle = \dfrac{1}{2} \times 12\times 6$

$\dashrightarrow\sf Area \: of \: triangle \triangle = \dfrac{1}{2} \times 72$

$\dashrightarrow\sf Area \: of \: triangle \triangle = \dfrac{72}{2}$

$\dashrightarrow\sf Area \: of \: triangle \triangle = 36 {m}^{2}$

$\therefore\sf Area \: of \: triangle \triangle = 36 {m}^{2}$

$\qquad \huge{ \underline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}$

Now, we know that

$\large{\boxed{ \sf Area \: of \: square \square = (side) \times (side)}}$

where,

• Side = 12m

So,

$\dashrightarrow\sf Area \: of \: square \square = (side) \times (side)$

$\dashrightarrow\sf Area \: of \: square \square = (12) \times (12)$

$\dashrightarrow\sf Area \: of \: square \square =144 {m}^{2}$

$\therefore\sf Area \: of \: square \square =144 {m}^{2}$

$\qquad \huge{ \underline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}$

Now, Area of total portion

> Area of triangle + Area of Square

where,

• Area of triangle = 36m²
• Area of Square = 144m²

So,

= 36 + 144 = 180m²

= 180m²

$\qquad \huge{ \underline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}$

we, know

$\large{\boxed{ \sf Area \: of \: square= (side) \times (side)}}$

where,

• Side = 1m

So,

$:\to \sf Area \: of \: square= (side) \times (side)$

$:\to \sf Area \: of \: square= (1) \times (1)$

$:\to \sf Area \: of \: square=1 {m}^{2}$

Now, using

$\large{\boxed{ \sf Area \: of \: Rectangle= l \times b}}$

where,

• Length, l = 1m
• Breadth, b = 3m

So,

$:\to\sf Area \: of \: Rectangle= l \times b$

$:\to\sf Area \: of \: Rectangle= 1 \times 3$

$:\to\sf Area \: of \: Rectangle = 3 {m}^{2}$

Now, area which should not be painted

> Area of Square + Area of Rectangle

where,

• Area of Square = 1m²
• Area of Rectangle = 3m²

So,

= 1 + 3 = 4m²

= 4m²

$\qquad \huge{ \underline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}$

Now, Area which should be Painted

✒ Area of Total portion - Area which should not be painted

✒ 180 - 4 = 176m²

✒ 176m²

Hence, Area which should be painted by two colors = 176m²

Answer 2

Answer:

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