Physics, asked by sahil400022, 9 months ago

Please answer me my questions and correct me

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Answered by yuvraj99975

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A. Pressure = 15 Pa

Area = $3m^{2}$

Force= Pressure × Area

Force = 15 × 3

Force = 45 Newtons

B. When converging the dimensions from cm to m we have :-

20 cm = 0.2m

10 cm = 0.1 m

5 cm = 0.05 m (placed height is on the sand)

According to Question,

To find the pressure exerted by brick on the sand = $\frac{Force}{Area} = \frac{20}{0.05}$ = 400 Pa.

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Answered by Madhav541

Answer:

(a)Force is 45N

(b)Pressure exerted by the brick is,

$1000 \frac{N}{ {m}^{2} }$

Explanation:

(a) Given Pressure is 15Pa

Surface Area is 3m^2

Then force is given P× A

F = 15 × 3

F = 45N

(b)Given Force applied by brick on sand is F = 20N

Dimensions of the brick is

Length = 20cm

Width = 10cm

Height = 5cm

Base area = Length × Width

$=> 20cm \times 10cm$

$= > \: 200 {cm}^{2}$

Now,

Pressure is given by,

P = F/base Area

$= > \frac{20N}{200 {cm}^{2} }$

$= > \frac{20 \times {10}^{ 4} N}{200 {m}^{2} }$

$= > 1000 \frac{N}{ {m}^{2} }$

That's all

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