Question

please answer me please answer me please answer me please answer me please answer me please answer me please answer me please answer me please answer me please answer me please answer me ​

Answer 1

Answer:

Suppose that side of 1st square is 'a' and 2nd square 's side is 'b'.

Then area of 1st square + 2nd square = a square + b square

a square +b square = 468

Now , perimeter of 1st square = 4a

and perimeter of 2nd square =4b

4a -4b = 24

4(a-b) =24

(a-b) = 6

a = 6+b

Now put the value of a that is 6+b in a square + b square

(b+6) square + b square = 468

Here after calculation value of b = 12

And value of a will be also 12

Answer 2

Answer:

Let x be the length of the side of First square and y be the length of side of the second square.

Then, x2+y2=468...(i)

Let x be the length of the side of the bigger square

4x−4y=24

⇒ x−y=6 or x=y+6...(ii)

Putting the value of x in terms of y from equation (ii), in equation (i), we get

(y+6)2+y2=468

⇒ y2+12y+36+y2=468

⇒ y2+18y−12y−216=0

⇒ y(y+18)12−(y+18)=0

⇒ (y+18)(y−12)=0

Either y+18=0 or y−12=0

⇒ y=−18 or y=12

But sides cannot be negative, so y=12

Therefore, x=12+6=18

Hence, sides of two square are 18m and 12m

Explanation:

Hope this will help you dear