Question

please answer me.. question 2​

Answer 1

$= > \: d = b {}^{2} - 4ac \\ = > - (2p + 1) {}^{2} - 4 \times 1 \times 6 = 0\\ = > - (4p {}^{2} + 1 + 4p) - 24 = 0 \\ = > - 4p {}^{2} - 1 - 4p - 24 = 0 \\ = > - 4 p{}^{2} - 4p - 25 = 0 \\ = > - 4(p {}^{2} + p) - 25 = 0 \\ = > p {}^{2} + p = 25 \div (- 4)$

bhai aab aap solve kar lo plzz ku ki mera net slowly chal raha hi