Math, asked by komalsingrajput, 1 year ago

please Answer Me question no 26??

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Answered by Mitanshu1711

Here's your answer☝️
Just interchanged what to prove.

PLEASE MARK AS BRAINLIEST

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ChoteMiyan: you can take tge thing from left to right or right to left

Mitanshu1711: No its correct

ChoteMiyan: since its not already proved you cant take things other side

Mitanshu1711: i only changed what we have to prove

ChoteMiyan: you cant change

Mitanshu1711: i am trying to prove it

Mitanshu1711: hold on

Mitanshu1711: It can be proved by solving both LHS and RHS

Mitanshu1711: solving LHS will come tan theta

Mitanshu1711: and solving RHS also will come tan theta

Answered by siddhartharao77

Step-by-step explanation:

LHS:

$=>\frac{1}{secA-tanA}-\frac{1}{cosA}$

$=>\frac{1}{secA-tanA}*\frac{secA+tanA}{secA+tanA}-secA$

$=>\frac{secA+tanA}{(secA-tanA)(secA+tanA)}-secA$

$=>\frac{secA+tanA}{sec^2A-tan^2A}-secA$

$=>\frac{secA+tanA}{1}-secA$

$=>secA+tanA-secA$

$=>tanA$

RHS:

$=>\frac{1}{cosA}-\frac{1}{secA+tanA}$

$=>secA-\frac{1}{secA+tanA}*\frac{secA-tanA}{secA-tanA}$

$=>secA-\frac{secA-tanA}{sec^2A-tan^2A}$

$=>secA-\frac{secA-tanA}{1}$

$=>secA-secA+tanA$

$=>tanA$

∴ LHS = RHS.

Hope it helps!

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