please answer me questions no 14,15 and gain 15 20 points and please dont post stupid answers ??
Answers
refer to attachment
Answer:
Step-by-step explanation:
Ans.14 Fig. is given below-
Join OP and OQ.
In OPS and OQS:
OP=OQ……Radius of circle
OPS=OQS=900 (Tangent is to the radius through the point of contact)
OS=OS….common
Therefore, by Right angle-Hypotenuse-Side criterion of congruence, we have
OPS OQS (RHS)
The corresponding parts of the congruent triangles are congruent.
POS = QOS……cpct,
OSP = OSQ ……..cpct
In quadrilateralPSQO:
POQ+PSQ=1800 as the total sum of interior angles in a quadrilateral=3600
POQ=PSQ=900
So OSP = OSQ = 45oAs PSQ=900
STC=900 sum of two co interior angles is 180 o.
SOT is an isosceles triangle having two sides:
OS=OT
Similarly, QOT = 45o
SOT = 90o
Ans.15
Sn=3n2-4n
S1=3-4=-1
S2=12-8=4
S1=A1= -1
S2=A1+A2
4= -1+A2
A2=5
S3=27-12=15
S3
=A1+A2+A3
15= -1+5+A3
A3=11
A.P:-1,5,11,..........
A=-1 , d=6
rth term= A+(r-1)d
=-1+(r-1)6
=-1+6r-6
=-7+6r
Plzzz mark my answer as Brainliest!!!
