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Answer:625
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Answer:
625 METER
Explanation:
GIVEN :
Speed of train , u = 90 × 5/18 km/h = 25 m/s
Acceleration , a = -0.5 m/s²
METHOD 1 :
∴ By first formula of motion
∵ v = u + at
∵ Train will be rest
∴ Final velocity, v = 0
∴ 0 = 25 - 0.5t
∴ 25 = 0.5t
∴ t = 50 sec
⇒ ∴ By second formula of motion
∵ S = ut + 1/2 at²
∴ S = 25 × 50 - 1/2 × 0.5 × 50²
= 1250 - 1/2 × 0.5 × 2500
= 1250 - 625
= 625 m
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⇒ METHOD 2 :
⇒∴ By third equation of motion
∴ v² = u² + 2as
∴ 2(0)= (25)2 + 2 ( - 0.5) s
∴ S = 625 m
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