Question

please answer me . send me by process of algebra , special identify
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Answer 1

Answer:

(x^2+y^2)=(x+y)^2-2xy

or (x-y)^2+2xy

Answer 2

Answer:

14. 116

15. 67

Step-by-step explanation:

14.

Given x+y=12 ---(1)

xy = 14 ------(2)

On Squaring both sides of equation (1) ,we get

(x+y)²= 12²

=> x²+2xy+y² = 144

By algebraic identity:

$(a+b)^{2}=a^{2}+b^{2}+2ab$

=> x²+y² +2×14=144

/* From (2)*/

=> x²+y²+28 = 144

=> x²+y² = 144-28

=> x²+y² = 116

Therefore, x²+y² = 116

15.

Given :

x - y = 7  

xy = 9

To find :

x² + y²

$(x-y)^{2} =(7)^{2}$

$x^{2} +y^{2} -2xy=49$

$x^{2} +y^{2} -2 X 9 =49$

$x^{2} +y^{2}-18=49$

$x^{2} +y^{2} =49+18$

$x^{2} +y^{2} = 67$

Hope it helps :)