Question

please answer me step by step please please please please please please please please please please please please please please please please​

Answer 1

Answer:

3x2by 4 by 4 =6

+4by6 5 x 7 v7

Answer 2

Answer:

Ok

Step-by-step explanation:

(1) 3(x+2)^2 = 108

=> 3(x^2+4+4x) = 108

=> x^2+4+4x = 36

=> x^2+4x-32 = 0

=> x^2+8x-4x-32x = 0

=> x(x+8) -4(x+8) = 0

=> (x-4) (x+8) = 0

=> x = 4 , -8

(2)

$4 \sqrt{3} {x}^{2} + 5x - 2 \sqrt{3 } = 0 \\ 4 \sqrt{3} {x}^{2} + 8x - 3x - 2 \sqrt{3} = 0 \\ 4x( \sqrt{3x} + 2) - \sqrt{3} ( \sqrt{3} x + 2) = 0 \\ ( \sqrt{3} x + 2)(4x - \sqrt{3} ) = 0 \\ x = \frac{ - 2}{ \sqrt{3} } \: \: . \: \: \frac{ \sqrt{3} }{4}$

(3)

$x {}^{2} - \frac{7}{2} x + \frac{3}{2} = 0 \\ 2 {x}^{2} - 7x + 3 = 0 \\ 2 {x}^{2} - 6x - x + 3 = 0 \\ 2x(x - 3) - 1(x - 3) = 0 \\ (2x - 1).(x - 3) = 0 \\ x = \frac{1}{2} \: \: . \: \: 3$