Question

please answer me that question is so hard​

Answer 1

Explanation:

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Yes

Answer 2

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Here is ur solution mate:

Given:

ABCD is a parallelogram

angle APB=angle CQD

To prove:

APB=~CQD

AP=CQ

Prove:

In triangle APB and triangle CQD

angle APB=angle CQD. [given 90]

DC=AB. [opposite sides]

angle QDC=angle ABP. [alternate angles]

By AAS congurence rule

APB=~CQD

(BY C.P.C.T)

AP=CQ

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