Question

Please answer me the answer fast

Answer 1

Answer:

1) d

2) d

3) a

4) cubic

5) root (or) zero

6) 0

7) 0

8) By using remainder theorem

x - 2 = 0 --> x = 2

3((2)^3) + 4((2)^2) - 5(2) - 5k = 0

24 + 16 - 10 - 5k = 0

k = 6

9) i) y^2 - 4y + 2y -8

= y(y - 4) + 2(y - 4)

= (y + 2)(y - 4)

ii) 21(x^2) - 7x + 6x - 2

= 7x(3x - 1) + 2(3x - 1)

= (7x + 2)(3x - 1)

10) (x - 1)(x - 2)(x - 3)

11) i) I don't know

ii) ii) a^3 - b^3 = (a - b)(a^2 + ab + b^2)

8x^3 - 27 = (2x - 3)(4x^2 + 6x + 9)

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