Question

please answer me the question ​

Answer 1

Answer:

$given \\ \alpha = 2 + \sqrt{3 } \\ \beta = 2 - \sqrt{3} \\ sum \: of \: zeroes \ \alpha + \beta \\ = 2 + \sqrt{3} + 2 - \sqrt{3} \\ = 4 \\ multple \: of \: zeroes. \\ \alpha \beta = (2 + \sqrt{3} )(2 - \sqrt{3} ) = 4 - 3 = 1 \\ polynomial \: equation. \\ {x}^{2} - ( \alpha + \beta )x + \alpha \beta = 0 \\ {x}^{2} - 4x + 1 = 0$

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Answer 2

Answer:

can't find solutions

Step-by-step explanation:

i don't know