please answer me the question.
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Answer:
a =50 degrees
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0
Answer:
(a)
since AB||DE
angle(CDE)=angle(CAB)
so angle(CDE)=70°
since ADC is straight line
angle(ADE)+angle(CDE)=180°
angle(ADE)+70°=180°
angle(ADE)=110°
(b)
sum of angles in a triangle =180°
in ∆CDE
50°+70°+angle(ECD)=180°
angle(ECD)=60°
IN ∆ABC
70°+60°+angle(ABC)=180°
angle(ABC)=50°
Hence angles are found.
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