Question

please answer me the question​

Answer 1

Question-;

A pair of the die is thrown. Find the probability of getting a sum of 10 or more, if 5 appears on the first die.

SOLUTION-;

In throwing a dice, total possible outcomes

= 1,2,3,4,5,6

For two dice, n(S) = 6×6 = 36

So, n(S)=6

Favorable cases where the sum is 10 or more with 5 on 1st die =(5,5),(5,6)

Event of getting the sum is 10 or more with 5 on 1st die = n(E) =2

Hence, the probability of getting a sum of 10 or more with 5 on 1st die

$= \frac{n(E)}{ n(S)}$

$= \frac{2}{36}$

$= \frac{1}{18}$

Answer 2

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Solution : - x = 120°

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