Please Answer Me the questions in the Capture File
Answers
1. The diameter of the circular track is given as 200 m. That is, 2r=200 m.
From this radius is calculated as Radius, r = 100 m.
In 40 sec the athlete complete one round. So, in 2 mins and 20 secs, that is, 140 sec the athlete will complete = 140 / 40 = 3.5 (three and a half) rounds.
One round is considered as the circumference of the circular track.
The distance covered in 140 sec = 2πr×3.5=2×3.14×100×3.5=2200 m.
For each complete round the displacement is zero. Therefore for 3 complete rounds, the displacement will be zero.
At the end of his motion, the athlete will be in the diametrically opposite position. That is, displacement = diameter = 200 m.
Hence, the distance covered is 2200 m and the displacement is 200 m.
2.From pont A to B
Distance covered=300m
Displacement=300m
Time taken=2 min 30 sec=(2×60)+30=150 sec
Average speed= Time taken / Displacement
=300/150= 2m/sec
Average velocity= Time Taken/Displacement
= 300/150= 2m/sec
From point A to C
Distance covered=300+100=400m
Displacement=300−100=200m
Time taken=3 min 30 sec=(3×60)+30=210 sec
Average speed= Time taken/ Distance taken =400/210=1.90 m/sec
Average velocity= Time taken/ Displacement
= 200/210 =0.95 m/sec