Question

Please answer me the right answer
Question in below attachment

Answer 1

Answer:

Step-by-step explanation:

Refer to the above file,

Let 'a' be the angle made with vertical

So,

$\sf{T\,cos(a)=mg\,\,\,\,\,\,\,\,\,...(1)}$

And,

$\sf{T\,sin(a)=ma\,\,\,\,\,\,\,\,\,\,\,...(2)}$

$\sf{Where,\,\,\, a=\dfrac{g}{\sqrt{3}}}$

So,

Dividing (2) by (1),

$\sf{tan(a)=\dfrac{ma}{mg}}$

$\sf{\implies\,tan(a)=\dfrac{a}{g}}$

$\sf{\implies\,tan(a)=\dfrac{g}{g\,\sqrt{3}}}$

$\sf{\implies\,tan(a)=\dfrac{1}{\sqrt{3}}}$

$\sf{\implies\,a=\dfrac{\pi}{6}}$