Question

Please answer me these questions.​

Answer 1

1. 20
2. 86
3. 38 sayadpo947t8ir9

Answer 2

Given data: (24÷6+1) - [25 ÷ 5 of 5 - 2 - {1 - (2 of 2 - 4 - 3)}]

                   56 - [47 - { 7 × 8 + ( 9 - 2 × 5)}]

                   [29 - ( - 2 ){ 6 - ( 7 - 3 )} ÷ { 3 × { 5 + ( - 3 ) × ( - 2)}]

To Find: The results.

Solution:

We have to use BODMAS - Bracket of Division, Multiplication, Add, Subtract.

1) (24÷6+1) - [25 ÷ 5 of 5 - 2 - {1 - (2 of 2 - 4 - 3)}] Solving bracket first

  = $(4+1)-[5of5-2-{5-(2of2-4-3)}]$

 $=(5)-[1-2-(1-4-3)] = 5 -[1-2-(-6)] \\=5 - (-8) = 5+8=13$; 13

2 ) 56 - [47 - { 7 × 8 + ( 9 - 2 × 5)}] = 64

$=56 - [ 47 - { 7$ × $8+(9-2$ × $5)}]$

$= 56-[47-{56+(9-10)$

$= 56-[47 -[56-1]]$

$=56-[47-55]\\=56+8 = 64$   ;                             ; 64

3) [29 - ( - 2 ){ 6 - ( 7 - 3 )} ÷ { 3 × { 5 + ( - 3 ) × ( - 2)}]

= $[29-(-2){6-(7-3))$ ÷ ${3$ × { $5 + (- 3)$ × $(-2)}]$

= $[29-(-2)(6-4)$ ÷$33$]

= $\frac{62}{33}$.

• Hence the solution is 13, 64 ,$\frac{62}{33}$.