please answer me this fast...1st and proper answer will be brainliest..
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x+y=30 this is equation 1
x-y= 14. this is equation2
therefore x=30-y from equation 1
also x= 14+y from equation 2
comparing both of them we get x= 8 now put x= 8 in equation 1 we get y=22
hope it will help u...
x-y= 14. this is equation2
therefore x=30-y from equation 1
also x= 14+y from equation 2
comparing both of them we get x= 8 now put x= 8 in equation 1 we get y=22
hope it will help u...
Answered by
1
ABCD is a rectangle.
opp. sides of a rectangle are equal
AB=CD
AD=BC
x+y=30 ..eq1
x-y=14 ..eq2
by elimination method
2x=44
x=44/2
x=22 units
put value of x in eq1
22+y=30
y=30-22
y=8 units
opp. sides of a rectangle are equal
AB=CD
AD=BC
x+y=30 ..eq1
x-y=14 ..eq2
by elimination method
2x=44
x=44/2
x=22 units
put value of x in eq1
22+y=30
y=30-22
y=8 units
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