Question

please answer me this. I will mark as the brainliest who ever gives me the correct answer.​

Answer 1

Answer:

1st graph shows uniform motion i.e. velocity is constant as time changes. Here acceleration is 0.

2nd graph shows uniform retardation. Acceleration decreases continuously by equal amounts with respect to time. It is a non - uniform motion since acceleration is not 0.

3rd graph shows a non - uniform motion divided into 3 parts. 1st part shows uniform acceleration, 2nd part shows uniform velocity (motion is uniform) and last part is uniform retardation.

Answer 2

$\huge\mathfrak\red{ANSWER}$

IN THE FIRST GRAPH SINCE THE LINE IS A STRAIGHT LINE THIS MEANS THAT THE BODY IS MOVING WITH A CONSTANT VELOCITY.

IN THE SECOND GRAPH THERE IS A SLOPE ON GRAPH THUS SLOPE INDICATES THAT THE BODY IS CHANGING ITS VELOCITY AT A PARTICULAR RATE.

IN THE THIRD GRAPH THE LINE STARTS FROM ORIGIN AND MOVES IN A STRAIGHT LINE AND THEN SLOPE FORMS.

THIS MEANS THAT THE BODY ACCELERATION AND MOVED WITH A CONSTANT ACCELERATION THEN.

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IMPORTANT ONES.- THESE WILL HELP YOU IN FUTURE.

ACCELERATION- IS THE RATE OF CHANGE OF VELOCITY.

DISPLACEMENT IS THE SHORTEST PATH BETWEEN INITIAL AND FINAL POSITION OF OBJECT.

RETARDATION IS CALLED NEGATIVE ACCELERATION.

VELOCITY AND DISPLACEMENT ARE VECTOR QUANTITIES.

THREE EQUATIONS OF MOTION ARE -

V = U + AT

S = UT + 1/2AT^2

V^2 = U^2 + 2AS.

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BY SCIVIBHANSHU

THANK YOU

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