Math, asked by tanish9639, 5 months ago

Please answer me this question .. ​

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Answered by urjashah2010
1

Answer:

We have,

(cosecθ−cotθ)^2  

=(  1/sinθ  -cos θ / sinθ)^2

=(1−cosθ /sinθ )^2

= (1-cosθ)/sin^2θ     = (1-cosθ)^2)/ 1-cos^2θ  [ coz, sin^2θ = 1-cosθ^2]

= (1−cosθ)^2/(1-cosθ) (1+cosθ)

= (1-cosθ)/(1+cosθ)

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