please answer me this question
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angle SOR=180°-50°=>130°
Angle( OSR+0RS)+SOR=180°
Let Angle OSR and ORS x°
x°+x°+130°=180°(ANGLE SUM PROPERTY)
2x=180-130
2x=50
x=25
AND EACH CORNER OF A RECTANGLE HAVE 90°
SO,
ANGLE RSO=25°
THEN,
ANGLE OSP=90-25=65°
Angle( OSR+0RS)+SOR=180°
Let Angle OSR and ORS x°
x°+x°+130°=180°(ANGLE SUM PROPERTY)
2x=180-130
2x=50
x=25
AND EACH CORNER OF A RECTANGLE HAVE 90°
SO,
ANGLE RSO=25°
THEN,
ANGLE OSP=90-25=65°
Harshgupta7689:
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