Please answer me this question fast... It's URGENT!!! (STD 8 ) Three consecutive are such that when they are taken in increasing order and multiplied by 2,3 and 4 respectively , they add up to 74. Find these numbers.
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Let the numbers be x, x+1 and x+2.
ATQ,
2x + 3(x+1) + 4(x+2) = 74
2x + 3x + 3 + 4x + 8 = 74
9x + 11 = 74
9x = 63
x = 7
Therefore, the numbers are : 7,8,9
ATQ,
2x + 3(x+1) + 4(x+2) = 74
2x + 3x + 3 + 4x + 8 = 74
9x + 11 = 74
9x = 63
x = 7
Therefore, the numbers are : 7,8,9
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