please answer me this question given in the attachment please
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The speed of light with critical angle 45° is "2.12×10⁸m/s"
The colour of light with the maximum critical angle is "Red"
The colour of light with the minimum critical angle is "Violet"
Explanation:
Since:-
C=45°
μ=1/sin C
=1/sin45°
=root2
We know that:-
v=c/μ
=(3×10⁸m/s)/root2
By calculating we get:
2.12×10⁸m/s
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